(x-2)^2=3(x+2)

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Solution for (x-2)^2=3(x+2) equation: 



(x-2)^2=3(x+2)

We move all terms to the left:

(x-2)^2-(3(x+2))=0



We calculate terms in parentheses: -(3(x+2)), so:

3(x+2)

We multiply parentheses

3x+6

Back to the equation:

-(3x+6)



We get rid of parentheses

(x-2)^2-3x-6=0

We add all the numbers together, and all the variables

-3x+(x-2)^2-6=0

We move all terms containing x to the left, all other terms to the right

-3x+(x-2)^2=6

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